An diofar eadar na mùthaidhean a rinneadh air "Cur-ris"
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New page: right|280px ’S e '''cur-ris''' an t-obrachadh matamataigeach a chuireas dà àireimh ri chèile gus an suim a dhèanamh. ’S e sin a... |
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Loidhne 114:
===Bheactaran===
Bheir an aon bhun-bheachd
[[Image:bheactar-1.png]]
Seo eisimpleir. Biodh
::<math> \mathbf{a} = x_a \hat{\mathbf{x}} + y_a \hat{\mathbf{y}} </math>
Gus an ceartuair, leig an seagh ''agus'' leis a’ chomharra “+” an seo, ged a chithear gur h-e cur-ris a th’ ann.
Mar an ceudna:
::<math> \mathbf{b} = x_b \hat{\mathbf{x}} + y_b \hat{\mathbf{y}} </math>
Faodar a-nis na codaichean-''x'' agus na codaichean-''y'' a chuir-ris, agus nithear ciall de chur-ris [[bheactar]]an '''c''' = '''a''' + '''b''' mar a leanas:
::<math> \mathbf{c} = x_c \hat{\mathbf{x}} + y_c \hat{\mathbf{y}} </math>
Far a bheil:
::
::<math> y_c = y_a + y_b \,\!</math>
Gabhar faicinn gum faighear an aon bhuil ma tha an dà [[bheactar]] '''a''' agus '''b''' air an cur ceann gu ceann. ’S e an suim aca am bheactar a tha a’ coileanadh an [[triantan|triantain]] – am bheactar bho thoiseach '''a''' gu deireadh '''b'''. ▼
::<math> \mathbf{a} + \mathbf{b} = (x_a + x_b) \hat{\mathbf{x}} + (y_a + y_b) \hat{\mathbf{y}} </math>
▲Gabhar faicinn gum faighear an aon bhuil ma tha an dà [[bheactar]]
[[Image:bheactar-2.png]]
Anns an aon dòigh, ma tha na codaichean de <math> \mathbf{a} </math>, an cois na h-axes ''x'' agus ''y'', na bheactaran:
::<math> \mathbf{x}_a = x_a \hat{\mathbf{x}}</math>
::<math> \mathbf{y}_a = y_a \hat{\mathbf{y}}</math>
...’s e am bheactar <math> \mathbf{a} </math> na suim:
::<math> \mathbf{a} = \mathbf{x}_a + \mathbf{y}_a = x_a \hat{\mathbf{x}} + y_a \hat{\mathbf{y}}</math>
[[Image:bheactar-3.png]]
===Machlagan===
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