An diofar eadar na mùthaidhean a rinneadh air "Cruinneadaireachd"

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b Corrigé avec Wikipedia:WikiProject Check Wikipedia - Headlines end with colon (v1.22)
Loidhne 55:
Biodh ''ABC'' na triantan co-chruinnein, agus biodh ''A'', ''B'' agus ''C'' nan ceàrn co-chruinnein aig gach gob an triantain. Biodh ''a'', ''b'' agus ''c'' nam faide arc mu choinneimh nan ceàrnan ''A'', ''B'' agus ''C'' fa leth. Gabhar a dhearbhadh gu bheil:
 
=== Foirmle bunaiteach triantanachd cho-chruinnein (am foirmle co-shìneiseach): ===
 
::<math>\cos a = \cos b \cos c + \sin b \sin c \cos A \,</math>
 
=== Am foirmle sìneiseach: ===
 
::<math>\frac{\sin A}{\sin a} = \frac{\sin B}{\sin b} = \frac{\sin C}{\sin c} \,</math>
 
=== Foirmlean eile le sìneasan agus co-shìneasan: ===
 
::<math> \sin a \cos B = \cos b \sin c - \sin b \cos c \cos A \,</math>
::<math> \sin a \cos C = \cos c \sin b - \sin c \cos b \cos A \,</math>
 
=== Foirmle nan ceithir pàirtean: ===
 
::<math> \cos a \cos C = \sin a \cot b - \sin C \cot B \,</math>
 
=== Samhlachasan Dhelambre: ===
 
::<math> \sin \tfrac {1}{2}c \sin \tfrac {1}{2}(A-B) = \cos \tfrac{1}{2}C \sin \tfrac {1}{2}(a-b) </math>
Loidhne 81:
 
 
=== Samhlachasan Napier: ===
 
::<math> \tan \tfrac {1}{2}(a+b) = \frac{ \cos \tfrac {1}{2}(A-B) } {\cos \tfrac {1}{2}(A+B)} \tan \tfrac {1}{2}c </math>